Page 121 - Demo

%u062c%u0645%u064a%u0639 %u0627%u0644%u062d%u0642%u0648%u0642 %u0645%u062d%u0641%u0648%u0638%u0629 %u0640 %u0627%u0625%u0644%u0639%u062a%u062f%u0627%u0621 %u0639%u0649%u0644 %u062d%u0642 %u0627%u0645%u0644%u0624%u0644%u0641 %u0628%u0627%u0644%u0646%u0633%u062e %u0623%u0648 %u0627%u0644%u0637%u0628%u0627%u0639%u0629 %u064a%u0639%u0631%u0636 %u0641%u0627%u0639%u0644%u0647 %u0644%u0644%u0645%u0633%u0627%u0626%u0644%u0629 %u0627%u0644%u0642%u0627%u0646%u0648%u0646%u064a%u0629121- 119-4 -Possible productivity of grain berth / per day= Number of daily operating hours x net operating time x net theoretical capacity of conveyor belt =18 x 90.0 x (48 x 90.0 = 360) = 5832 tons/day.5 -Possible productivity of silo berth annually= Possible productivity of the silo berth / per day x [(number of days in the year - number of working days) x the appropriate rate of occupancy of the berth] = 5832x [(365 - 45) x 80.0] = 1492992 tons/year.6- Despite the significant decrease in actual performance from the performance that can be achieved as we have previously explained, the daily productivity of the actual performance (195 x 18 = 3510 tons / day) far exceeds the daily quantity that grain silos management undertakes to empty (2000 tons / day). Perhaps the justification for this situation is to avoid congestion at berth and the fines it imposes due to delay, which is equivalent to $5,000 for each day of delay after the expiry of period specified for unloading the ship. the possible productivity of equipment for unloading bulk wheat from ships is related to capacity of the grain silos, which is supposed to be the main objective of its establishment in ports is to unload cargoes of ships into the country and not store them. It helps in achieving this that the grain is often pulled to the packing plants on a timely basis, and the wheat is pulled directly from ship out of port to mills. %u2022 For container berth Possible productivity of container berth (i) = h x u x c x d whereh = number of working hours per day.u = berth occupancy rate.C = Average productivity of crane per hour.d = number of cranes operating on quay or berth.Example: If you know that the actual number of daily working hours at container terminal is 18 hours, and berth occupancy rate is 80%, excluding lost time, which is equivalent to 5 days, and the average productivity of possible crane per hour is equivalent to 20 containers / hour, and there are two cranes on the berth moving with a length of two berths handle cargo containers to and from berth and ship. Required:1 -Calculate the average possible productivity of the container berth / per day.2 -Calculate the average possible productivity of the container berth / annually.3 -If you know that the actual container traffic at this berth is 28,654 containers, of which 15,294 are descending, and 13,360 inbound containers. How do you explain the decrease or increase in the occupancy rate of the container berth?The solution1 -Possible productivity of container berth (i) = h x u x c x d= 18 x 8.0 x 20 x 2 = 576 containers/day